# I'm getting not a useful error when I try to start Slicer Jupyter kernel, how to debug?

**URL:** https://discourse.slicer.org/t/im-getting-not-a-useful-error-when-i-try-to-start-slicer-jupyter-kernel-how-to-debug/13530
**Category:** Support
**Created:** [September 17, 2020, 4:04pm UTC](https://discourse.slicer.org/t/im-getting-not-a-useful-error-when-i-try-to-start-slicer-jupyter-kernel-how-to-debug/13530 "2020-09-17T16:04:37Z")
**Posts on this page:** 1
**Showing post:** 12

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### Author: ![lassoan](https://sea2.discourse-cdn.com/flex002/user_avatar/discourse.slicer.org/lassoan/32/13_2.png) [@lassoan](https://discourse.slicer.org/u/lassoan)
#### Post date: [September 20, 2020, 5:22pm UTC](https://discourse.slicer.org/t/im-getting-not-a-useful-error-when-i-try-to-start-slicer-jupyter-kernel-how-to-debug/13530/12 "2020-09-20T17:22:09Z")

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> /home/yousefi/Slicer-4.11.0-2020-09-19-linux-amd64/bin/…/bin/PythonSlicer: /software/spackages/linux-centos8-x86\_64/gcc-8.3.1/anaconda3-2020.07-4obfocw3kpymwz7obsjukroelfwutobz/lib/libuuid.so.1: no version information available (required by /lib64/libSM.so.6)

I don’t know how or why anaconda’s libuuid is found instead of the system libuuid. Can you check if your environment has some conda variables? Was this Slicer started from some virtual Python environment?

Does `./PythonSlicer -m jupyter --no-warn-script-location` work from a terminal?

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